How to find the third largest number in an array using a loop?

Question

Aryan Kumar · Answer

Here is a Java program to find the third largest number in an array using a loop:
Code snippet
import java.util.*;
public class ThirdLargestInArray {
    public static void main(String[] args) {
        // Create an array
        int[] arr = {12, 13, 1, 10, 34, 11};
        // Initialize the three largest elements as minus infinite
        int first = Integer.MIN_VALUE;
        int second = Integer.MIN_VALUE;
        int third = Integer.MIN_VALUE;
        // Iterate through the array
        for (int i = 0; i andlt; arr.length; i++) {
            // If the current element is greater than the first largest element
            if (arr[i] > first) {
                // Update the third largest element
                third = second;
                // Update the second largest element
                second = first;
                // Update the first largest element
                first = arr[i];
            } else if (arr[i] > second andand arr[i] != first) {
                // Update the third largest element
                third = second;
                // Update the second largest element
                second = arr[i];
            } else if (arr[i] > third andand arr[i] != second) {
                // Update the third largest element
                third = arr[i];
            }
        }
        // Print the third largest element
        System.out.println("The third largest element is " + third);
    }
}
This program will print the following output:
Code snippet
The third largest element is 11

Rahul Roi · Answer

// Online C# Editor for free
// Write, Edit and Run your C# code using C# Online Compiler
using System;
public class HelloWorld
{
    public static void Main(string[] args)
    {
        int[] num={2,1,3,7,6,8,4,9};
        Console.WriteLine (FindLargetValue(num));
        //Console.WriteLine (FindLargetValue(num, -2));
        Console.WriteLine (FindLargetValue(num, 3));
        Console.WriteLine (FindLargetValue(num, 1));
    }
    public static int FindLargetValue(int[] array , int position=0)
    {
        Array.Sort(array);
        Array.Reverse(array);
        if(positionandlt;0 || position> array.Length)
        {
            throw new Exception('Index not found');
        }
        return position==0 ? array[position] :  array[position-1];
    }
}
If we put index in negative value then throw an exception “Index Not Found”,
like -1, -0, -2and 
If you put position value higher than length of array then throw an exception 
“Index Not Found” .
Output is →
9
7
8
and

Tehran Noorani · Answer

This is the simple C# program to find the third largest number from a given integer array.
using System;
namespace Test
{
 class ThirdLargeNumber
 {
   static void Main(string[] args)
   {
   int[] num={2,1,3,7,6,8,4,9};
    LargestThirdNumber(num);
   }
     internal static void LargestThirdNumber(int[] arr)    
     {    
         int num1 = int.MinValue;    
         int num2 = int.MinValue;    
         int num3 = int.MinValue;    
         foreach (int i in arr)    
         {    
             if (i > num1)    
             {    
                 num3 = num2;    
                 num2 = num1;    
                 num1 = i;    
             }    
             else if (i > num2 andand i != num1)    
             {    
                 num3 = num2;    
                 num2 = i;    
             }    
             else if (i > num3 andand i != num2 andand i != num1)    
             {    
                 num3 = i;    
             }    
         }    
         Console.WriteLine(num3); ;    
     }
 }
}
Output: 7
and

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How to find the third largest number in an array using a loop?

Revati S Misra

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